5=1/(9^2y)

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Solution for 5=1/(9^2y) equation: 


D( y )

9^2*y = 0

9^2*y = 0

9^2*y = 0

81*y = 0 // : 81

y = 0

y in (-oo:0) U (0:+oo)

5 = 1/(9^2*y) // - 1/(9^2*y)

5-(1/(9^2*y)) = 0

5-(9^-2*y^-1) = 0

-1/81*y^-1 = -5 // : -1/81

y^-1 = 405

-1 < 0

1/(y^1) = 405 // * y^1

1 = 405*y^1 // : 405

1/405 = y^1

y = 1/405

y = 1/405

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